Barbiturates are hypnotic agents. Veronal is | vedclass

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(D) The synthesis of Veronal involves the following steps:$1$. Diethyl malonate $(CH_2(CO_2Et)_2)$ reacts with ethyl iodide $(EtI)$ in the presence of

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(D) The synthesis of Veronal involves the following steps:$1$. Diethyl malonate $(CH_2(CO_2Et)_2)$ reacts with ethyl iodide $(EtI)$ in the presence of a base $(EtO^-)$ twice to undergo double alkylation at the active methylene carbon,forming diethyl diethylmalonate,$(Et)_2C(CO_2Et)_2$.$2$. This diethyl diethylmalonate then undergoes a condensation reaction with urea $(NH_2CONH_2)$ in the presence of a base to form $5,5-$diethylbarbituric acid,which is known as Veronal.$3$. The structure of Veronal consists of a pyrimidine ring with two ethyl groups at the $5^{th}$ position and two carbonyl groups at the $4^{th}$ and $6^{th}$ positions,with the $2^{nd}$ position also being a carbonyl group.$4$. Comparing this with the given options,the structure corresponding to $5,5-$diethylbarbituric acid is represented by option $D$.

Barbiturates are hypnotic agents. Veronal is a derivative of barbituric acid. It can be synthesized by the following sequence,then the structure of veronal $(P)$ is :
$CH_2(CO_2Et)_2$ $\xrightarrow[EtI]{EtO^-}$ $\xrightarrow[EtI]{EtO^-}$ $\xrightarrow{Urea}$ $(P)$

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Barbiturates are hypnotic agents. Veronal is a derivative of barbituric acid. It can be synthesized by the following sequence,then the structure of veronal $(P)$ is :$CH_2(CO_2Et)_2$ $\xrightarrow[EtI]{EtO^-}$ $\xrightarrow[EtI]{EtO^-}$ $\xrightarrow{Urea}$ $(P)$